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Prove algebraically that 0.72 recurring is equal to 8/11.

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Final answer:

To prove that 0.72 recurring equals 8/11, define x as 0.72 recurring, multiply by 100 to obtain an equation, subtract the original number from this new equation, solve for x and simplify to demonstrate that x equals 8/11.

Step-by-step explanation:

To prove algebraically that 0.72 recurring is equal to 8/11, we'll use variables and algebraic manipulation. Let's define x to be the repeating decimal 0.72 (where 72 is the repeating part).

First, we write it as:

x = 0.727272...

To eliminate the recurring part, we can multiply x by 100 since the repeating part is two digits long:

100x = 72.727272...

Now, we subtract the original x from this new equation:

100x - x = 72.727272... - 0.727272...

Which simplifies to:

99x = 72

Dividing both sides by 99 to solve for x:

x = 72 / 99

Both numerator and denominator are divisible by 9, so we simplify:

x = 8 / 11

Thus, we've algebraically proven that the recurring decimal 0.72 is indeed equal to 8/11.

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