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Computer keyboard failures can be attributed to electrical defects or mechanical defects. A repair facility currently has 25 failed keyboards, 6 of which have electrical defects and 19 of which have mechanical defects. How many ways are there to randomly select 5 of these keyboards for a thorough inspection (without regard to order)?

a.Use combo formula with 5 and 25 25!/(5!*20!)
b.Use combo formula with 6 and 25 25!/(6!*20!)
c.Use combo formula with 5 and 5 5!/(5!*20!)
d.None of the above

1 Answer

3 votes

Final answer:

The correct option is a. Use combo formula with 5 and 25, 25!/(5!*20!).

Step-by-step explanation:

The correct option is a. Use combo formula with 5 and 25, 25!/(5!*20!).

To find the number of ways to randomly select 5 keyboards for thorough inspection out of 25 failed keyboards, we can use the combination formula. The combination formula is given by nCk = n! / (k!(n-k)!), where n is the total number of objects and k is the number of objects being selected.

In this case, there are 25 failed keyboards and we need to select 5 for inspection, so the formula becomes 25C5 = 25! / (5!(25-5)!) = 25! / (5!20!). Calculating this gives us the total number of ways to select 5 keyboards for inspection.

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