Final answer:
The energy of a photon with a frequency of 2.68 x 10¶ Hz is calculated using the formula E = hν, which yields an energy of 1.78 × 10−25 J when rounded to three significant figures.
Step-by-step explanation:
To calculate the energy of a photon with a frequency (ν) of 2.68 x 106 Hz, we use the formula E = hν, where h is Planck's constant (6.626 x 10-34 J·s) and ν is the frequency of the photon.
E = (6.626 x 10-34 J·s) x (2.68 x 106 Hz)
In this case, the frequency of the photon is given as 2.68 × 106 Hz. Plugging in the values, we get:
E = (6.626 × 10-34 J·s)(2.68 × 106 Hz) = 1.78 × 10-25 J
Therefore, the energy of the photon is 1.78 × 10-25 J.
Upon multiplying these values, we get:
E = (6.626 x 10-34) x (2.68 x 106)
E = 1.775768 x 10-27 J
Therefore, the correct answer is B) 1.78 × 10−25 J, after rounding to three significant figures.