Question

An aeroplane accelerates down a runway at 3.20m/​​​​​​s2 for 32.8 seconds until lifts off from the ground. What is the distance travelled before takeoff?

a.1721m
b.1722m
c.1723m
d.1720m

Answer 1

Using the kinematic equation for distance with an initial velocity of zero, the distance travelled by the aeroplane before takeoff is calculated to be approximately 1721 meters, corresponding to answer choice (a).

Step-by-step explanation:

The question asks us to calculate the distance travelled by an aeroplane before takeoff, given that it accelerates at 3.20 m/s² for 32.8 seconds from rest. To find the distance, we can use the kinematic equation that relates distance (s), acceleration (a), and time (t) when initial velocity (u) is zero:

s = ut + ½at²

Since the aeroplane starts from rest, u = 0, so the equation simplifies to:

s = ½at²

Now we plug in the values:

s = ½ × 3.20 m/s² × (32.8 s)²

s = ½ × 3.20 m/s² × 1075.84 s²

s = ½ × 3441.088 m

s = 1720.544 m

Rounded to the nearest whole number, the distance travelled before takeoff is approximately 1721 meters, so the correct answer is (a) 1721 m.