Final answer:
The pH of a 0.33 M solution of H2SO4 (sulfuric acid) is approximately 0.
Step-by-step explanation:
The pH of a solution can be determined by the concentration of hydrogen ions ([H+]). In the case of sulfuric acid (H2SO4), it is a strong acid that dissociates completely in water. Each molecule of H2SO4 will produce 2 H+ ions in solution. Since the concentration of H2SO4 is 0.33 M, the concentration of H+ ions is twice that, which is 0.66 M.
Now, to find the pH, we take the negative logarithm (base 10) of the hydrogen ion concentration:
pH = -log [H+]
Substituting the concentration value, we get:
pH = -log (0.66) ≈ 0.18
Therefore, the pH of a 0.33 M solution of H2SO4 (sulfuric acid) is approximately 0.