Question

Given a slope of -4/5 and passing through the point (15, -3), find the equation of the line.

a) y=-4x+21
b) y=-4/5x-3
c) y=-4/5x+21
d) y=-4x-3

Answer 1

To find the equation of a line given a slope and a point, use the point-slope form of a linear equation.

Step-by-step explanation:

To find the equation of a line given a slope and a point, we can use the point-slope form of a linear equation, which is y - y₁ = m(x - x₁). In this case, the slope is -4/5 and the point is (15, -3).

Substituting the values into the point-slope form, we have y - (-3) = (-4/5)(x - 15).

Simplifying the equation gives us y + 3 = (-4/5)(x - 15).

Expanding and rearranging the equation, we get y = -4/5x + 21.

Therefore, the equation of the line is y = -4/5x + 21.