Final answer:
The question pertains to the physical properties of plates in a capacitor, which are typically more than 1/4" in thickness. Additionally, the electric potential at a certain distance from a conducting plate can be found using the relationship V = E d, with given electric field strength and potential difference values.
Step-by-step explanation:
The question appears to relate to the concept of electric fields and capacitance in physics, specifically concerning parallel conducting plates in a capacitor form. To address the student's question regarding the thickness of plates, plates are typically defined as more than 1/4" in thickness. Therefore, the correct answer to the student’s question would be (C) More than.
For the second part of the question, the potential at a point 1.00 cm from a plate (with the lowest potential at zero volts) in an electric field can be found by using the electric field equation V = E d where V is the potential difference, E is the electric field strength, and d is the distance. The potential difference V equals the product of the electric field strength and the distance from the zero-potential plate.
In the provided context where the strength of the electric field between two plates and the potential difference are given, one can calculate the distance between the plates using the equation d = V / E, where d is the distance, V is the potential difference, and E is the electric field strength.