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What is the value of xyz at the end of the fifth execution of the following function?

void func() {int xyz = 10; xyz++;}

1 Answer

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Final answer:

The value of xyz at the end of the fifth execution of func() is 11. The xyz variable is local and resets each time func() is called; it does not accumulate between calls.

Step-by-step explanation:

The student has asked a question related to the execution of a piece of code, specifically what the value of xyz will be at the end of the fifth execution of the function func(). The function includes the following code:

void func() {
int xyz = 10;
xyz++;
}

Given the function, each time it is called, the variable xyz is initialized to 10 and then incremented by 1. However, since xyz is a local variable to the function func(), it is re-created every time the function is called and is not preserved between function calls. After five executions of func(), the value of xyz is still 11 at the end of each individual function call, not accumulating between calls.

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