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What is the value of xyz at the end of the fifth execution of the following function?

void func() {static int xyz = 10; xyz++;}

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Final answer:

The value of the static variable xyz after the fifth execution of the function is 15, as it gets incremented by 1 each time the function is called, starting from its initial value of 10.

Step-by-step explanation:

The student has asked about the value of a static variable xyz after the fifth execution of a function in a programming context. When the function func() is called, it contains a static variable xyz initialized to 10. Each time the function is executed, xyz is incremented by 1. So, at the first call, xyz becomes 11, at the second call it becomes 12, and so forth. By the end of the fifth execution, xyz will have been incremented 5 times.

Therefore, the value of xyz at the end of the fifth execution will be:

10 (initial value) + 1 (first execution) + 1 (second execution) + 1 (third execution) + 1 (fourth execution) + 1 (fifth execution) = 15.

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