Question

I need some help with with question:

How could you prepare 100 ml of a 0.40 mol/L of MgSO4 solution from a stock solution of 2.0 mol/L MgSO4. And then how would u prepare it?

Answer 1

C1V1=C2V2

C1 is 2.0mol/l

V1=?

C2=.4mol/L

V2=100ml or for this 0.1L

V1 is 20ml

Best way to prepare this is to measure out 20ml of the 2 molar solution and add 80mL to it to get to 100mL

Step-by-step explanation: