36.3k views
5 votes
Differentiate y=√64−x² .⋅8arcsin(x³/8).

User Jacksbox
by
8.2k points

1 Answer

4 votes

Final answer:

To differentiate the given function, apply the chain rule and product rule. The derivative of y is -8x * arcsin(x³/8) + 3x²√(64-x²)/8.

Step-by-step explanation:

To differentiate the given function, we will need to apply the chain rule and product rule. Let's break down the steps:

  1. First, differentiate the square root function. The derivative of √(64-x²) is -x/√(64-x²).
  2. Next, differentiate the arcsin function. The derivative of arcsin(x³/8) is (3x²)/[8√(64-x²)].
  3. -x/√(64-x²) * 8arcsin(x³/8) + √(64-x²) * (3x²)/[8√(64-x²)].

Simplifying the expression, we get:

dy/dx = -8x * arcsin(x³/8) + 3x²√(64-x²)/8.

User Screamer
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories