Final answer:
The zeros of the quadratic function f(x) = x² + 4x – 12 are x = -6 and x = 2.
Step-by-step explanation:
To find the zeros of the quadratic function f(x) = x² + 4x – 12, we can use the quadratic formula. The formula is given by: x = (-b ± √(b² - 4ac)) / (2a). Substituting the values from the quadratic function, we get: x = (-4 ± √(4² - 4(1)(-12))) / (2(1)) = (-4 ± √(16 + 48)) / 2 = (-4 ± √64) / 2 = (-4 ± 8) / 2. Therefore, the zeros of f(x) are x = -6 and x = 2.