Final answer:
The potential energy stored in the spring is approximately 0.247625 Joules.
Step-by-step explanation:
The potential energy stored in a spring can be calculated using the formula PE = 1/2kx², where PE is the potential energy, k is the spring constant, and x is the displacement of the spring. In this case, the spring constant is 74 N/m and the displacement is 8.5 cm. Converting the displacement to meters, we have x = 0.085 m. Plugging these values into the formula, we get PE = 1/2(74 N/m)(0.085 m)². Evaluating this expression gives us the potential energy stored in the spring.
PE = 1/2(74 N/m)(0.085 m)²
= 1/2(74 N/m)(0.007225 m²)
= 0.247625 J
Therefore, the spring stores approximately 0.247625 Joules of potential energy when stretched by 8.5 cm.