Question

A 3.2 kg box of fruit slides 4.4 m down a ramp, inclined at 30.0° from the horizontal. If the box slides at a constant velocity of 5.00 m/s, what is the work done by the weight of the box?

Answer 1

The work done by the weight of the box sliding down the inclined ramp can be calculated using the formula Work = Force x Distance x cosine(theta), where Force is the weight of the box, Distance is the horizontal distance the box slides, and theta is the angle between the ramp and the horizontal. Plugging in the given values, we find that the work done by the weight of the box is 88.704 Joules.

Step-by-step explanation:

To calculate the work done by the weight of the box, we can use the formula:

Work = Force x Distance x cosine(theta)

Where:

• Force is the weight of the box, which can be calculated as mass x gravitational acceleration (F = mg).
• Distance is the horizontal distance the box slides down the ramp (4.4 m).
• Theta is the angle between the ramp and the horizontal (30 degrees).

Plugging in the values:

Work = (mg) x (distance) x cos(theta)

= (3.2 kg x 9.8 m/s^2) x 4.4 m x cos(30 degrees)

= 88.704 J

So, the work done by the weight of the box is 88.704 Joules.