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If I create three arrays of 5 ints right after each other, where in memory were they allocated?

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Final answer:

Three sequentially created arrays of integers in a program will be allocated in memory on the stack and placed one after another unless dynamic memory allocation is used, in which case they may reside in the heap. The exact location in memory is determined at runtime, and array elements within each array are contiguous.

Step-by-step explanation:

When you create three arrays of 5 integers (ints) right after each other in a program, they are allocated in the heap or stack memory, depending on how they are declared and the language specifics. In many programming languages like C and C++, if you allocate the arrays within a function without using dynamic memory allocation, they will be placed on the stack. They will be laid out sequentially in memory, one array after the other, and the precise location within the stack is determined at runtime. The stack grows downwards, so the address of each subsequent variable or array will typically be lower than the one before it. In the case of dynamic memory allocation (e.g., using malloc in C), the arrays will be situated within the heap segment, and their positioning is managed by the system's memory allocator and can be non-contiguous. It is also worth noting that array elements within each array are contiguous.

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