229k views
1 vote
What happens when ΔH and ΔS are both negative?"

A) Reaction is spontaneous.
B) Reaction is non-spontaneous.
C) Depends on temperature.
D) Equilibrium is reached.

1 Answer

3 votes

Final answer:

The spontaneity of a reaction where both ΔH and ΔS are negative depends on temperature, because ΔG = ΔH - TΔS and the outcome is temperature-dependent.

Step-by-step explanation:

When ΔH (enthalpy change) and ΔS (entropy change) are both negative, the spontaneity of a reaction depends on the temperature. According to the Gibbs free energy equation, ΔG = ΔH - TΔS, where T is the temperature in Kelvin. Since ΔH is negative, the first term is negative; however, because ΔS is also negative, the second term (-TΔS) will become positive at any positive temperature value. Therefore, the spontaneity will depend on whether the positive -TΔS term is sufficient to outweigh the negative ΔH term.

At low temperatures, the ΔG may be negative, making the reaction spontaneous. Conversely, at high temperatures, the -TΔS term may dominate and ΔG becomes positive, hence the reaction is non-spontaneous. Therefore, the correct answer is C) Depends on temperature.

User Lindsey Simon
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.