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In the system x+y+3z=600 and x+y+z=400, what is the value of x+y?

User Pyrocater
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1 Answer

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Final answer:

The value of x+y in the given system of equations is 300.

Step-by-step explanation:

To find the value of x+y in the system of equations x+y+3z=600 and x+y+z=400, we can solve for x and y separately and then add them together.

First, subtract the second equation from the first equation to eliminate z:

x+y+3z - (x+y+z) = 600 - 400

2z = 200

z = 100

Substitute the value of z back into the second equation and solve for x+y:

x+y+100 = 400

x+y = 400 - 100

x+y = 300

Therefore, the value of x+y is 300.

User Philippe Grondier
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