Final answer:
The mass of C₂H₂produced is 4.0625 g and the mass of Ca(OH)₂ produced is 11.5625 g.
Step-by-step explanation:
The balanced equation for the reaction is:
CaC₂(s) + 2H2O(I) → C₂H₂(g) + Ca(OH)₂(aq)
From the equation, we can see that 1 mole of CaC2 reacts to produce 1 mole of C₂H₂. Using the molar mass of CaC2 (64 g/mol), we can calculate the number of moles of CaC2 by dividing the mass of CaC2 (10 g) by its molar mass. This gives us 0.15625 moles of CaC₂.
Since the mole ratio between CaC₂ and C₂H₂is 1:1, we have 0.15625 moles of C₂H₂.
Now, we can calculate the mass of 0.15625 moles of C₂H₂by multiplying the moles of C₂H₂by its molar mass (26 g/mol).
Therefore, the mass of C₂H₂ produced is 4.0625 g.
To determine the mass of Ca(OH)₂ produced, we need to consider the moles of CaC₂ and the stoichiometry of the reaction.
Since 1 mole of CaC₂ reacts to produce 1 mole of Ca(OH)₂, we have 0.15625 moles of Ca(OH)₂. The molar mass of Ca(OH)₂ is 74 g/mol, so the mass of Ca(OH)₂ produced is 11.5625 g.