Question

You take a gas volume of 4 units (liters or cu ft) in a flexible container from the surface to a depth of 78'/23.6m in sea water. What will the new volume be, and what will the density be compared to the surface?

1) V = 1.19, D = 8
2) V = 1.19, D = 3.36
3) V = 3.40, D = 1.34
4) V = 2x, D = the same

Answer 1

The new volume of the gas will be 2 times smaller and the density will remain the same compared to the surface.

Step-by-step explanation:

The new volume of the gas can be calculated using Boyle's Law, which states that the product of the initial volume and pressure is equal to the product of the final volume and pressure.

Since the pressure at a depth of 78'/23.6m in sea water is higher than at the surface, the gas will compress and its volume will decrease.

To calculate the new volume, we can use the equation:

V1 x P1 = V2 x P2

Where:
V1 = initial volume
P1 = initial pressure
V2 = final volume
P2 = final pressure

Since the density of the gas remains the same, the density compared to the surface will also remain the same.

Therefore, the correct answer is 4) V = 2x, D = the same.