Final answer:
To find the average weight of individual beef tenderloins in a case that weighs 52 pounds and 8 ounces, we convert the total weight to ounces and divide by six. The average weight is 140 ounces per tenderloin.
Step-by-step explanation:
The student wishes to know the average weight of individual beef tenderloins if a case of six tenderloins weighs 52 pounds and 8 ounces. To calculate the average weight, we first convert the total case weight to ounces, since each tenderloin piece likely weighs less than a pound and accuracy is vital. There are 16 ounces in one pound, so the case weighs a total of (52 pounds x 16 ounces per pound) + 8 ounces = 840 ounces.
Next, we divide the total weight by the number of tenderloin pieces. The calculation is as follows: 840 ounces / 6 pieces = 140 ounces per piece. This is the average weight of each beef tenderloin in ounces.
It is worth noting for packaging purposes that each tenderloin piece should be labeled in ounces for precision, as suggested by industry practices when dealing with packages of steak that are usually less than a pound.