28.7k views
0 votes
what are the chances of two individuals having a child with tay-sachs if both individuals are not of ashkenazi or french-canadian descent?

User Tardis Xu
by
8.5k points

1 Answer

4 votes

Final answer:

Two carrier parents have a 25% chance of having a child with Tay-Sachs disease, regardless of their descent. The disorder is autosomal recessive, and the risk is related to carrier status, not ethnicity.

Step-by-step explanation:

The chances of two individuals having a child with Tay-Sachs disease if both individuals are carriers of the gene but are not of Ashkenazi or French-Canadian descent can still be significant. Tay-Sachs is an autosomal recessive disorder, meaning that a child must inherit two copies of the recessive gene (one from each parent) to exhibit the disease. If both parents are carriers, there is a 25% chance that any given child will have Tay-Sachs, a 50% chance the child will be a carrier like the parents, and a 25% chance the child will inherit two non-mutated alleles, thus being unaffected non-carrier.

For example, if we compare this to another autosomal recessive condition, such as cystic fibrosis (CF), two carrier parents (Ff) have a 25% chance of having a child with CF (ff). Similarly, two parents who are carriers for the Tay-Sachs gene have a 25% chance of having a child who is affected by Tay-Sachs disease. The actual expression of the disease would not be influenced by ethnicity; instead, it is the frequency of the carrier state in a population that varies with ancestry, such as the Ashkenazi Jewish or French-Canadian populations where carrier rates are higher.

User Sachin Aggarwal
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories