Final answer:
The Lewis structure for BrO3- consists of a central bromine atom double bonded to three oxygen atoms with lone pairs, enclosed in brackets with a negative charge outside.
Step-by-step explanation:
The Lewis structure for the BrO3- ion can be drawn by following several steps. First, you need to determine the total number of valence electrons available, which is 24 from the three oxygen atoms (6 electrons each), plus 7 from the bromine atom, and an extra one due to the negative charge, totalling to 32 electrons. Then, draw a skeleton structure with bromine as the central atom and single bonds connecting it to three oxygen atoms.
Next, you'll need to complete the octets around the oxygen atoms by adding lone pairs. Each oxygen will have three lone pairs, using up 18 electrons and leaving 14 electrons. You will then place the remaining electrons around the bromine atom to satisfy its octet. Since there are no electrons left for the central atom after placing lone pairs on the oxygens, you might need to form double bonds between bromine and one or more of the oxygen atoms to satisfy the octet rule.
Finally, since BrO3- is a polyatomic ion, enclose the structure in square brackets and denote the charge outside the brackets. The correct Lewis structure for this molecule includes three oxygen atoms double-bonded to a central bromine atom, each oxygen having two lone pairs, and the central bromine having one lone pair. The charge of -1 is indicated outside the brackets, completing the structure for BrO3-.