Question

a 13.5-kv 20-mva,0.8-pf-lagging,60-hz,two-pole, y-connected steam-turbine generator has a synchronous reactance of 5.0 per phase and an armature resistance of 0.5 per phase. this generator is operating in parallel with a large power system (infinite bus).(a) what is the magnitude of e, at rated conditions?

Answer 1

The magnitude of the generated voltage, e, can be calculated using the formula e = V - I(Zsyn + jXsyn) where V is the terminal voltage, I is the armature current, Zsyn is the synchronous impedance, and Xsyn is the synchronous reactance.

Step-by-step explanation:

The magnitude of the generated voltage, e, can be calculated using the formula e = V - I(Zsyn + jXsyn)

where V is the terminal voltage, I is the armature current, Zsyn is the synchronous impedance, and Xsyn is the synchronous reactance. In this case, V is 13.5 kV, I can be calculated using the power formula I = P / (V * sqrt(3)), P is the rated power (20 MVA), and sqrt(3) is the square root of 3. The synchronous impedance is given by Zsyn = sqrt(Ra2 + Xsyn2), where Ra is the armature resistance. Xsyn is given as 5.0 per phase, Ra as 0.5 per phase, and Xsyn can be calculated as Xsyn = V2 / S, where S is the rated apparent power (20 MVA).

Substituting the given values into the formulas and solving, we can find the magnitude of e at rated conditions.