Question

An electron having de-Broglie wavelength λ is incident on a target in a X−ray tube. Cut-off wavelength of emitted X- ray is :

(Symbols have their usual meaning)
A. 2m²c²λ²/h²
B. 0
C. hc/mc
D. 2mcλ²/h

Answer 1

The cut-off wavelength of emitted X-ray in an X-ray tube can be calculated using the de Broglie wavelength of the incident electron. Therefore, the correct option is A.

Step-by-step explanation:

The cut-off wavelength of emitted X-ray in an X-ray tube can be calculated using the de Broglie wavelength of the incident electron. The de Broglie wavelength is given by λ = h / mv, where h is Planck's constant, m is the mass of the electron, and v is its velocity. The cut-off wavelength can then be determined by the formula λc = hc / K, where K is the kinetic energy of the emitted X-ray.

Therefore, the correct answer is option A: 2m²c²λ²/h².