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The number of moles of water released during one mole synthesis of dibenzalacetone is/are ......

(a) 1
(b) 2
(c) 3
(d) 4

User Ossek
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Final answer:

For the synthesis of one mole of dibenzalacetone from acetone and benzaldehyde, the balanced chemical reaction shows that two moles of water are released as byproducts. The stoichiometry of the reaction provides the mole ratio of the reactants and products.

Step-by-step explanation:

The synthesis of dibenzalacetone involves a condensation reaction known as the Aldol condensation, whereby acetone is reacted with benzaldehyde in the presence of a base. This particular reaction is an example of a crossed Aldol condensation, which results in the formation of dibenzalacetone and the release of water as a byproduct. To deduce the number of moles of water released, we must examine the stoichiometry of the balanced chemical reaction.

Each molecule of acetone combines with two molecules of benzaldehyde to form one molecule of dibenzalacetone, releasing two molecules of water in the process. Therefore, for every one mole of dibenzalacetone synthesized, two moles of water are released. It is important to note that the stoichiometry is determined by the coefficients in the balanced chemical equation, and this ratio must be maintained for the reaction to take place according to the equation.

Even though the provided reference talks about the hydration of aluminum chloride (AlCl3 · 6H2O), it shows that the chemical equation is used to represent the proportion of reactants and products, including water. However, in the synthesis of dibenzalacetone, the balanced equation has a mole ratio of 1:1:2 when it comes to benzaldehyde, acetone, and water respectively.

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