Final answer:
The correct answer is option (C) 30. By equating the total amount stored in paise to the value of coins in the given ratio, we find that Shyam has 30 fifty paise coins.
Step-by-step explanation:
The correct answer is option (C) 30.
Shyam has stored Rs. 35 in the form of 1 rupee coins and 50 paise coins in the ratio 2:3. To find the number of 50 paise coins, we need to first express the total amount in paise which is 35 x 100 = 3500 paise. Following the given ratio, let the number of 1 rupee coins be 2x and the number of 50 paise coins be 3x. Therefore, the total value in paise will be 100(2x) + 50(3x) = 3500 paise.
Solving for x, we have:
200x + 150x = 3500
350x = 3500
x = 3500 / 350
x = 10
Since the number of 50 paise coins is 3x, we multiply 10 by 3 to get 30.
Therefore, Shyam has 30 fifty paise coins.
Let's solve the problem:
We are given that the ratio of 1 rupee coins to 50 paise coins is 2 : 3.
Let the number of 1 rupee coins be 2x.
Then, the number of 50 paise coins will be 3x.
The value of the 1 rupee coins is 2x * 1 = 2x rupees.
The value of the 50 paise coins is 3x * 0.50 = 1.50x rupees.
According to the problem, the total value of the coins is Rs. 35.
So, we have the equation:
2x + 1.50x = 35
3.50x = 35
x = 10
Therefore, the number of 50 paise coins is 3x = 3 * 10 = 30.