Final answer:
The intensity ratio of maxima and minima in the interference pattern, given an amplitude ratio of 3:2, would be 25:1, where intensity is proportional to the square of the amplitude. This ratio is not listed among the provided options, indicating a possible error in the question.
Step-by-step explanation:
If the amplitude ratio of two interfering beams is 3:2, then to find the intensity ratio of maxima and minima in the interference pattern, we need to use the relation that intensity is proportional to the square of the amplitude. For two waves with amplitudes A₁ and A₂ interfering, the maximum intensity (Iₚ₁₀) occurs when the waves are in phase and is given by (A₁ + A₂)², while the minimum intensity (Iₚ₉₉) occurs when the waves are out of phase and is given by (A₁ - A₂)². Substituting the given amplitudes of 3 and 2, we get the maximum intensity as (3+2)² = 25, and the minimum intensity as (3-2)² = 1. Hence, the ratio of maximum to minimum intensity is 25:1, which is not one of the options provided in the question. It is possible that there was an error in the provided options.