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If the elevation in boiling point of a solution of 10 g of solute (molecular weight = 100) in 100 g of water is ΔTb, the ebullioscopic constant of water is

A. 10
B. 100Tb
C. ΔTb
D. ΔTb/10

User Xjcl
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1 Answer

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Final answer:

The question is about calculating the change in the boiling point of a solution per unit change in concentration based on the known ebullioscopic constant of water. We use the formula for boiling point elevation, with the given molecular weight and masses to determine the molality, which then helps calculate the requested value.

Step-by-step explanation:

The question involves the concept of boiling point elevation in Chemistry, specifically relating to colligative properties of solutions. The formula to calculate the boiling point elevation (ΔTb) is given by ΔT = Kb × m, where Kb represents the molal boiling-point elevation constant or ebullioscopic constant of the solvent, and m is the molality of the solution.

For the solvent water, the Kb is 0.51°C/m. In this case, the molecular weight of the solute is 100, and we have 10 g of solute in 100 g of water. The molality (m) is calculated by taking the number of moles of solute divided by the kilograms of solvent, which comes out to 1 mol/kg or 1 m. Thus, with ΔTb representing the boiling point elevation for this solute concentration, the question simplifies to finding ΔTb/10, which effectively would be the ΔTb value for a 0.1 m solution of the given solute in water.

User Michael Allen
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