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What volume of decinormal K₂Cr₂O₇ solution would be needed to convert 1.19g of tin to stannic chloride in acidic medium?(Z of Sn=119g/mol

a. 400 ml
b. 200 ml
c. 250 ml
d. 300 ml

User Bambi
by
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1 Answer

1 vote

Final answer:

The volume of 0.1 N K₂Cr₂O₇ solution needed to convert 1.19 g of Sn to SnCl₄ cannot be determined without the balanced chemical equation for the reaction in an acidic medium, which would provide the necessary stoichiometry.

Step-by-step explanation:

To find the volume of decinormal (0.1 N) K₂Cr₂O₇ solution required to convert 1.19 g of tin (Sn) to stannic chloride (SnCl₄) in an acidic medium, we first calculate the number of moles of Sn. Using the molar mass of Sn (119 g/mol), we get 0.01 moles of Sn. The balanced chemical equation for the reaction between Sn and K₂Cr₂O₇ in an acidic medium will provide the stoichiometry necessary to determine the volume of K₂Cr₂O₇ needed. However, without the balanced equation, we can't proceed further with the calculation.

The general idea in a titration, such as with K₂Cr₂O₇ and Fe²⁺, is that the moles of the titrant and analyte are related by the stoichiometry of the balanced chemical equation. In a similar case, where it required a certain volume of K₂Cr₂O₇ to titrate Fe²⁺, it was found that each mole of K₂Cr₂O₇ reacts with six moles of Fe²⁺. Such information helps to understand the relation between the substances during the reaction.

User Stephane Martin
by
8.1k points
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