Question

one mole of non linear triatomic gas at 27 °C undergoes reversible adiabatic expansion from 16 to 18 find the temperature of gases

Answer 1

To find the final temperature of a non-linear triatomic gas after an adiabatic expansion, convert the initial temperature to Kelvin, use the adiabatic process formula with the volumes given, and solve for the final temperature in Kelvin.

Step-by-step explanation:

The student is asking about the final temperature of a non-linear triatomic gas undergoing reversible adiabatic expansion. To solve this, one must use the adiabatic process equation for a non-linear triatomic gas. The specific heat ratio (γ) for a non-linear triatomic gas is typically 4/3. The formula relating initial and final temperatures (T1 and T2) and volumes (V1 and V2) in an adiabatic process for a reversible expansion is given as T1V1^(γ-1) = T2V2^(γ-1).

Given that the initial temperature (T1) is 27 °C (which is 300 K when converted to Kelvin), initial volume (V1) is 16 (arbitrary units), final volume (V2) is 18 (arbitrary units), and γ = 4/3 for a non-linear triatomic gas, we can solve for T2.

Use the following steps to find the final temperature :

1. Convert the initial temperature from Celsius to Kelvin.
2. Apply the adiabatic process formula with the given volumes and calculate T2.
3. Keep in mind that the temperature obtained will be in Kelvin, and if needed, convert it back to Celsius.