Question

Passage of the current for 548 seconds through a silver coulometer results in the deposition of 0.746g of silver. What is the current in A?

(A) 1.22

(B) 1.16

(C) 1.07

(D) 1.00

Answer 1

To find the current in amperes (A), we need to convert the mass of silver to moles, calculate the charge in coulombs, and then use the formula I = Q/t. The current is approximately 1.22 A.

Step-by-step explanation:

To determine the current in amperes (A), we can use the formula:

I = Q/t

Where:

I is the current in amperes (A)

Q is the charge in coulombs (C)

t is the time in seconds (s)

In this case, we are given that the charge is 0.746g of silver and the time is 548 seconds.

First, we need to convert the mass of silver to the number of moles using the molar mass of silver:

molar mass of Ag = 107.87 g/mol

So, the number of moles of silver is:

moles of Ag = mass of silver / molar mass of Ag

Next, we need to calculate the charge in coulombs using Faraday's constant:

1 mole of electrons = 1 Faraday = 96,485 C

So, the charge in coulombs is:

charge = moles of Ag x 96,485 C/mol

Finally, we can calculate the current using the formula:

current = charge / time

By substituting the values, we get the current:

current = (mass of silver / molar mass of Ag) x 96,485 C/mol / time

Plugging in the values, we get:

current = (0.746g / 107.87 g/mol) x 96,485 C/mol / 548 s = 1.22 A

Therefore, the current is approximately 1.22 A.