The solution to the system of equations 5x + y = 0 and 5x + 2y = 30 is x = -6 and y = 30, obtained through substitution by solving for y and substituting the result.
To find the solution to the system using substitution or elimination, let's choose one method. I'll demonstrate using substitution.
Substitution:
1. Solve the first equation for one variable, say \(y\).
![\[ 5x + y = 0 \] \[ y = -5x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/yf3onnvxn94y5f6sk1vusezf0jfc776oaj.png)
2. Substitute this expression into the second equation.
![\[ 5x + 2y = 30 \] \[ 5x + 2(-5x) = 30 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/twmtf2lb774m5okgse44oq3gtb61k95j6p.png)
3. Simplify and solve for x.
![\[ 5x - 10x = 30 \] \[ -5x = 30 \] \[ x = -6 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/bbsmhkmabfcx4ukiqc7064iknvi79kl9fy.png)
4. Substitute the value of x back into the expression for y.
![\[ y = -5(-6) \] \[ y = 30 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8943p383xi83hc6myfa4biigz5lrr2mgsl.png)
So, the solution to the system is x = -6 and y = 30.