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In a hydrogen atom, the binding energy of the electron in the ground state is E1 then the frequency of revolution of the electron in the nth orbit is

A. 2E1/nh
B. 2E1n/h
C. E1/nh
D. E1n/h

1 Answer

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Final answer:

The frequency of revolution of an electron in the nth orbit of a hydrogen atom, given the binding energy E1 in the ground state, is represented by option C, which is E1/nh. Therefore, the correct option is C.

Step-by-step explanation:

The student is asking about the frequency of revolution of the electron in the nth orbit of a hydrogen atom, given that the binding energy of the electron in the ground state is E1. According to the Bohr model of the hydrogen atom, the energy levels are quantized and can be expressed by the formula En = -13.6 eV / n², where n is the principal quantum number.

The frequency of revolution, or the frequency of the electron's orbit, can be related to the energy difference between the nth and ground states, so the correct formula involves the energy and Planck's constant h. The actual relationship is derived from the energy of a photon emitted in a downward transition in terms of frequency, ΔE = hf. Therefore, the frequency of revolution of the electron in the nth orbit is correctly represented as E1 / nh, which corresponds to option C in the given question.