Final answer:
To maximize electric power consumption, two resistors should be connected in parallel to the battery. The total energy consumed by 3 bulbs, 4 fans, and an electric heater in a household for a month of 31 days is 147.18 kWh, costing Rs 588.72 at the rate of Rs 4/kWh.
Step-by-step explanation:
To maximize the electric power consumed by two resistors with resistances R1 ohm and R2 ohm when connected to a battery of emf V volts, the resistors should be connected in parallel. In this configuration, the total resistance is decreased, allowing more current to flow from the battery, which increases the power consumed according to P=IV, where I is current and V is voltage.
For the energy consumption in a household, we can calculate the total amount used by various appliances and their duration of use over a period of 31 days. The formula for energy consumed in kilowatt-hours (kWh) is Energy (kWh) = Power (Watts) × Time (hours) × Number of Days × (1/1000) to convert Watts to Kilowatts.
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- Bulbs: 3 × 60W each × 3 hours/day × 31 days × (1/1000) = 16.98 kWh
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- Fans: 4 × 100W each × 8 hours/day × 31 days × (1/1000) = 99.2 kWh
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- Heater: 2 kWh × 0.5 hours/day × 31 days = 31 kWh
Total energy consumed = 16.98 kWh + 99.2 kWh + 31 kWh = 147.18 kWh
The cost of energy consumption at Rs 4 per kWh is:
Cost = 147.18 kWh × Rs 4/kWh = Rs 588.72