Question

Two trains running in opposite directions at 36 kmph and 45 kmph. a man sitting in the slower train passes the faster train in 8 sec. length of faster train is?

a. 80 m
b. 120m
c. 150m
d. 180m

Answer 1

The length of the faster train is 180 meters. Option D

How to solve

1. Calculate the relative speed:

First, convert the speeds to m/s:

36 kmph = (36 * 5/18) m/s = 10 m/s

45 kmph = (45 * 5/18) m/s = 12.5 m/s

Then, calculate the relative speed by adding their speeds since they are moving in opposite directions:

Relative speed = 10 m/s + 12.5 m/s = 22.5 m/s

2. Calculate the distance traveled by the man:

Since the man passes the faster train in 8 seconds, multiply the relative speed by the time:

Distance = Relative speed * Time = 22.5 m/s * 8 s = 180 meters

3. Calculate the length of the faster train:

This distance is equal to the total length of the faster train because the man passes it completely.

Faster train length = Distance = 180 meters

Therefore, the length of the faster train is 180 meters.