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A body of mass 10kg is moving with an initial speed of 20ms.The body stops after 5s due to friction between body and the floor.The value of the coefficient of friction is:

A. 0.2
B. 0.4
C. 0.5
D. 0.3

1 Answer

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The value of the coefficient of friction is B. 0.4

How to find the value of the coefficient of friction?

According to Newton's second law of motion, the net force (F) acting on the body is equal to its mass (m) multiplied by its acceleration (a):

F = ma

In this case, the only force acting against the motion is the frictional force (f). Therefore:

f = ma = 10 kg * (-4 m/s ²)

= -40 N

Since the body is resting on the floor, the normal force is equal to the weight of the body: N = mg

= 10 kg * 9.81 m/s ²

= 98.1 N

Therefore, the coefficient of friction can be calculated as:

μ = f / N = -40 N / 98.1 N

= 0.408

User Richard Belleville
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