(a) For frequency of 620 THz, the energy of the photon is 2.56 eV.
(b) For frequency of 3.10 GHz, the energy of the photon is 1.28 x 10⁻⁵ eV.
(c) For frequency of 46 MHz, the energy of the photon is 1.9 x 10⁻⁷ eV.
(d) The wavelength of 620 THz, 3.10 GHz and 46 MHz is 4.84 x 10⁻⁷ m, 0.097 m and 6.52 m respectively.
How to calculate the energy and wavelength of the photons?
(a) For frequency of 620 THz;
E = hf
where;
- h is Planck's constant
- f is the frequency
E = (620 x 10¹² ) x (6.626 x 10⁻³⁴)
E = 4.108 x 10⁻¹⁹ J
E = 4.108 x 10⁻¹⁹ J / 1.602 x 10⁻¹⁹ J = 2.56 eV
The wavelength is;
λ = c / f
λ = ( 3 x 10⁸ ) / ( 620 x 10¹² )
λ = 4.84 x 10⁻⁷ m
(b) For frequency of 3.1 GHz;
E = hf
E = (3.1 x 10⁹ ) x (6.626 x 10⁻³⁴)
E = 2.05 x 10⁻²⁴ J
E = 2.05 x 10⁻²⁴ J / 1.602 x 10⁻¹⁹ J = 1.28 x 10⁻⁵ eV
The wavelength is;
λ = c / f
λ = ( 3 x 10⁸ ) / ( 3.1 x 10⁹ )
λ = 0.097 m
(c) For frequency of 46 MHz;
E = hf
E = (46 x 10⁶ ) x (6.626 x 10⁻³⁴)
E = 3.05 x 10⁻²⁶ J
E = 3.05 x 10⁻²⁶ J / 1.602 x 10⁻¹⁹ J = 1.9 x 10⁻⁷ eV
The wavelength is;
λ = c / f
λ = ( 3 x 10⁸ ) / ( 46 x 10⁶ )
λ = 6.52 m