159k views
2 votes
A body is projected vertically up. At certain height 'h' above the ground,. its PE and KE are in the ratio 1:4. Then at what height above the ground PE and KE will be in the-ratio 4:1

A. h4
B. 5 h
C. h/5
D. 4 h

1 Answer

3 votes

Final answer:

The height above the ground where the potential energy (PE) and kinetic energy (KE) will be in the ratio 4:1 is directly proportional to v².

Step-by-step explanation:

To find the height above the ground where the potential energy (PE) and kinetic energy (KE) will be in the ratio 4:1, we can use the relationship between PE and KE.

According to the relationship 2gh=v², where g is the acceleration due to gravity and h is the height, we can set up the equation for the given ratio:

PE/KE = 1/4

Using the equation 2gh=v², we can substitute the ratio PE/KE with 1/4 and solve for h:

1/4 = 2gh/v²

Rearranging the equation to solve for h:

h = v²/(8g)

Therefore, the height h above the ground where PE and KE will be in the ratio 4:1 is directly proportional to v².

The correct answer is option D. 4h.

User Stephen Ngethe
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories