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A light pointer fixed to one prong of a tuning fork touches gnetly a smoked vertical plate. The fork is set vibrating and the plate is allowed to fall freely. 8 complete oscilllations are counted when the plate falls through 10cm.What is the frequency of the tuning fork?

A. 360 Hz
B. 280 Hz
C. 560 Hz
D. 56 Hz

1 Answer

6 votes

The frequency of the tuning fork is D. 56 Hz

How to find frequency?

To find the frequency of the tuning fork, find the relationship between the number of oscillations, the distance fallen, and the time taken for the plate to fall:

Number of oscillations (n) = 8

Distance fallen (d) = 10 cm

= 0.1 m

Frequency (f) = number of oscillations / time

Time (t) can be calculated using the equation for freefall:

t² = 2d / g,

where g = acceleration due to gravity (approximately 9.81 m/s²).

Substitute the given values:

t² = 2 × 0.1 m / 9.81 m/s²

≈ 0.0204 seconds

Take the square root to get the time:

t ≈ 0.143 seconds

Calculate frequency:

f = n / t

f = 8 oscillations / 0.143 seconds

f ≈ 56 Hz

Therefore, the frequency of the tuning fork is 56 Hz. This means it vibrates 56 times per second, producing the corresponding sound wave with a frequency of 56 Hz.

User Yasuhiro TATSUNO
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