Final answer:
The conductivity of a 0.01 M solution of an electrolyte can be calculated using Ohm's Law and the cell constant of the conductivity cell. The conductivity is found to be 1.
Step-by-step explanation:
The conductivity of a solution can be calculated using Ohm's Law which states that V = IR, where V is the voltage, I is the current, and R is the resistance. In this case, the resistance of the cell is given as 1000 ohms. The cell constant, which relates the conductivity of the solution to the resistance of the cell, is given as 0.146 cm^(-1). To find the conductivity, we can rearrange the equation as V/R = I. The voltage can be found using the formula V = kCD, where k is the cell constant, C is the concentration of the electrolyte, and D is the distance between the electrodes. We can substitute the values into the equation to find the conductivity.
Given:
V = kCD
R = 1000 ohm
k = 0.146 cm^(-1)
C = 0.01 M
D = unknown
I = unknown
Since we are given the resistance of the cell and the concentration of the electrolyte, we can rearrange the equation as V = I x R and substitute the values into the equation to find the voltage. Then we solve for the current using the equation V = kCD. Finally, we substitute the current and the voltage into the equation I = V/R to find the conductivity.
Conductivity = I/R = V/(R x V/R) = V/V = 1
Therefore, the conductivity of the 0.01 M solution of the electrolyte is 1.