Question

Two resistance wires on joining in parallel the resultant resistance is 6/5 ohms. One of the wire breaks the effective resistance is 2 ohms. The resistance of the broken wire is

Answer 1

When two resistors are connected in parallel, the equivalent resistance is calculated using the formula 1/Req = 1/R1 + 1/R2. By applying this formula, we can determine that the resistance of the broken wire in this problem is 3/5 ohms.

Step-by-step explanation:

When two resistors are connected in parallel, the equivalent resistance is given by the formula:

1/Req = 1/R1 + 1/R2

In this case, the resultant resistance is 6/5 ohms, so we have:

1/(6/5) = 1/R1 + 1/R2

Simplifying this equation gives:

R1 + R2 = 6/5

Now, when one of the wires breaks, the effective resistance becomes 2 ohms.

Let's call the resistance of the broken wire R3. Since R1 and R2 were in parallel, their equivalent resistance was 6/5. So we have:

1/(6/5) = 1/R3 + 1/2

Simplifying this equation gives:

R3 = 3/5 ohms