Question

An object of volume 4cc and density 1.2g/cc is fully submerged in water (but does not touch the floor) of the vessel. (Take g):

(a) The object will float.

(b) The object will sink.

(c) The object will partially float.

(d) The object's behavior cannot be determined.

Answer 1

Comparing the density of the object (1.2g/cc) to that of water (1.0g/cc), it is determined that the object will sink because its density is greater than that of water. Option B is correct.

Step-by-step explanation:

The question asks whether an object with a volume of 4cc and a density of 1.2g/cc will float or sink when fully submerged in water. To determine this, we compare the density of the object to the density of the water. Since the density of water is 1.0g/cc, which is less than the density of the object, the object will sink. This observation is based on the principle that if an object's density is greater than the fluid in which it is submerged, it will sink.

To find the density of an object using the water displacement method, as in the given example of a 240-g rock that displaces 89.0 cm³ of water, you divide the mass of the object by the volume of water displaced. Therefore, the density of the rock is calculated as follows:

Density = Mass / Volume Displaced
Density = 240g / 89.0 cm³
Density ≈ 2.70 g/cm³