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The decomposition of N₂​O₅​ in CCl₄​ at 318 K has been studied by monitoring the concentration of N₂​O₅ in the solution. Initially, the concentration of N₂​O₅​ is 2.33 mol L⁻¹, and after 184 minutes, it is reduced to 2.08 mol L⁻¹. The reaction takes place according to the equation 2N₂​O₅​(g)→4NO₂​(g)+O₂​(g).

Calculate the average rate of this reaction in terms of hours, minutes, and seconds.

User Prasham
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Final answer:

To calculate the average rate of the decomposition of N2O5, take the change in concentration (0.25 mol L^-1) divided by the time period in the desired unit, providing the rates in hours, minutes, and seconds.

Step-by-step explanation:

The student is asking how to calculate the average rate of the reaction for the decomposition of dinitrogen pentoxide (N2O5) in carbon tetrachloride (CCl4) at 318 K. The average rate is found by determining the change in concentration over a given time period.

The initial concentration of N2O5 is 2.33 mol L-1 and after 184 minutes, it is 2.08 mol L-1. To find the average rate, we'll use the formula:

Average rate = ∆[Concentration] / ∆[Time]

The change in concentration, ∆[Concentration], is (2.33 - 2.08) mol L-1 = 0.25 mol L-1. The change in time, ∆[Time], is 184 minutes. However, since the student wants the rate in different time units, we'll convert 184 minutes to hours and seconds as well:

  • 184 minutes = 3.067 hours
  • 184 minutes = 11040 seconds

Hence, the average rate in terms of hours is 0.08153 mol L-1 h-1, in minutes it is 0.001359 mol L-1 min-1, and in seconds it is 0.00002265 mol L-1 s-1.

User Jchristof
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