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When a spaceship is at a distance of two times the radius of Earth, what is the gravitational force on that spaceship?

a. F=GMm/(2R)²
b. F=GMm/2R​
c. F=GMm/(2R)³
d. F=GMm/(2R)²

User Estevan
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1 Answer

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Final answer:

The gravitational force on a spaceship at a distance of two Earth radii from the center of Earth is given by the formula F = GMm / (2R)². This is derived from Newton's law of universal gravitation with the separation being two times Earth's radius. Option A is correct.

Step-by-step explanation:

When a spaceship is at a distance of two times the radius of Earth from the center of the Earth, the gravitational force on that spaceship is given by Newton's law of universal gravitation:

F = G×M×m / r²

Where F is the gravitational force, G is the gravitational constant (6.674 × 10-11 N·m²/kg²), M is the mass of the Earth, m is the mass of the spaceship, and r is the separation between the center of masses of the two objects. If r is equal to two times the radius of Earth (2R), the equation becomes:

F = G×M×m / (2R)²

Therefore, the correct answer is a. F = GMm / (2R)².

The correct formula to calculate the gravitational force on the spaceship when it is at a distance of two times the radius of Earth is F=GMm/(2R)².

Here, G represents the gravitational constant, which is a universal constant that is the same everywhere in the universe. Its value is 6.67 × 10^-11 Nm²/kg².

M represents the mass of Earth and m represents the mass of the spaceship. R represents the radius of Earth.

By substituting the given values into the formula, you can calculate the gravitational force on the spaceship.

User Claudiu Claw
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