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A particle executes harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/s² respectively. The amplitude of oscillation is

A. 0.28 m
B. 0.36 m
C. 0.53 m
D. 0.61 m

1 Answer

3 votes

The amplitude of oscillation of the particle which executes simple harmonic is 0.61 m (option D)

How to calculate the amplitude of oscillation?

Amplitude of oscillation is related to the acceleration according to the following formula:

a = ω²A

Where

  • a is the acceleration of object
  • ω is the angular velocity
  • A is the amplitude of oscillation

Now, we shall apply the above formula to calculate the amplitude of the oscillation. This is explained below:

  • Angular velocity of particle (ω) = 3.5 rad/sec
  • Maximum acceleration of particle (a) = 7.5 m/s²
  • Amplitude of oscillation (A) =?

a = ω²A

7.5 = 3.5² × A

7.5 = 12.25 × A

Divide both sides by 12.25

A = 7.5 / 12.25

A = 0.61 m

Therefore, the correct answer to the question is option D

User Ashir
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