Final answer:
The electrostatic attraction between two point charges or a point charge and a charged conducting sphere at a distance r from each other remains the same if the distance is greater than the radius of the sphere.
Step-by-step explanation:
The question asks about the electrostatic attraction between two charges when one is given to a conducting sphere. According to Coulomb's Law, the force of attraction between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
Considering a conducting sphere of radius R with a charge placed on it, we know from the principles of electrostatics that the sphere's outer electric field behaves as if the charge were concentrated at the center of the sphere, provided the observation point is outside the sphere (r > R).
Therefore, if two conducting spheres with charges are placed at a distance r from each other, with r being greater than the radius of either sphere, the electrostatic force between them would be equivalent to the force between two point charges at the same distance. Hence, the correct answer is that the electrostatic attraction would be the same (C. f=f₀).