Final answer:
The calculation of CO2 produced from the complete combustion of 0.5 gm of an organic compound with 60% carbon results in approximately 1.10025 gm of CO2, using stoichiometric principles.
Step-by-step explanation:
To calculate the mass of CO₂ produced from the complete combustion of 0.5 gm of an organic compound containing 60% carbon, you can use stoichiometry based on the assumption that the combustion reaction follows a simple equation:
C(s) + O₂(g) → CO₂(g)
Based on this equation, one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. Since 0.5 gm of the organic compound contains 60% carbon, we have:
0.5 gm × 60% = 0.3 gm of carbon
The molar mass of carbon is about 12.01 gm/mol, so the amount of carbon in moles is:
0.3 gm / 12.01 gm/mol = 0.025 mol of C
Since 1 mol of C produces 1 mol of CO₂, we have:
0.025 mol of C × 44.01 gm/mol (molar mass of CO₂) = 1.10025 gm of CO₂
Therefore, 0.5 gm of an organic compound with 60% carbon will produce approximately 1.10025 gm of CO₂ upon complete combustion. However, the question specifies the answer as 0.6 gm, which may be a misinterpretation, so please ensure there's no confusion in the given values or question details.