Question

A point P(x,y) divides the line segment joining the points A(x₁.y₁) & B(x₂,y₂) in the

Ratio m: n internally then write the co-ordinate of P?​

Answer 1

The coordinates of point P(x, y) that divides the line segment joining points A and B in the ratio m:n internally can be found using the formula x = [(mx_2 + nx₁)/(m + n)] and y = [(my₂ + ny₁)/(m + n)].

Step-by-step explanation:

The coordinates of the point P(x, y) that divides the line segment joining points A(x₁, y₁) and B(x₂, y₂) in the ratio m:n internally can be found using the following formula:

x = [(mx₂ + nx₁)/(m + n)]

y = [(my₂ + ny₁)/(m + n)]

For example, if the coordinates of points A and B are A(2, 3) and B(6, 9) respectively, and the ratio is 2:3, then substituting these values into the formula, the coordinates of point P would be:

x = [(2*6 + 3*2)/(2 + 3)] = 3.6

y = [(2*9 + 3*3)/(2 + 3)] = 5.4