Question

Find number of moles of Na₃PO₄ which contain as many ions as are present in 1368gm of Al₂(SO₄)₃. (Assuming complete dissociation of salt and no reaction with H₂)

Answer 1

To find the number of moles of Na₃PO₄ that contain the same number of ions as are present in 1368 g of Al₂(SO₄)₃, you need to calculate the number of moles of Al₂(SO₄)₃, determine the number of ions in 1 mole of Al₂(SO₄)₃, and use the ratio of ions in Na₃PO₄ to calculate the number of moles of Na₃PO₄.

Step-by-step explanation:

To find the number of moles of Na₃PO₄ that contain the same number of ions as are present in 1368 g of Al₂(SO₄)₃, we first need to calculate the number of moles of Al₂(SO₄)₃. Then, we determine the number of ions in 1 mole of Al₂(SO₄)₃. Next, we use the ratio of ions in Na₃PO₄ to calculate the number of moles of Na₃PO₄.

Step 1: Calculate moles of Al₂(SO₄)₃ using its molar mass.

Step 2: Determine the number of moles of ions in 1 mole of Al₂(SO₄)₃.

Step 3: Use the ratio of ions in Na₃PO₄ to calculate the number of moles of Na₃PO₄.

So, the number of moles of Na₃PO₄ that contain the same number of ions as 1368 g of Al₂(SO₄)₃ is XX moles.