Final answer:
The excess pressure inside a mercury drop with a surface tension of 0.465 Nm⁻¹ and a diameter of 6 mm is 310 Pascal (Pa).
Step-by-step explanation:
The student's question relates to the concept of surface tension and excess pressure inside a droplet. Specifically, it's about calculating the excess pressure inside a mercury drop using the given surface tension value of mercury, which is 0.465 Nm⁻¹, and the drop's diameter of 6 mm. The formula for excess pressure (P) inside a spherical droplet is given by P = 2σ/R, where σ is the surface tension and R is the radius of the droplet.
Firstly, we need to convert the diameter to meters to match the units of the surface tension: Diameter (d) = 6 mm = 0.006 m. The radius (R) is half of the diameter, so R = 0.003 m.
Now, we can calculate the excess pressure inside the drop:
P = 2 × 0.465 Nm⁻¹ / 0.003 m = 310 N/m², which is the same as 310 Pa since 1 Pa equals 1 N/m².